Amy showed us what she had done.
On prob number 1. I have all deaths total being 100, the people who will survive for 34 years as being 65 (compliment of 35) in the table. So is the probability 65/100?
I interpreted this to be asking the probability that a person lives 3 or 4 years or more after the diagnosis. If this is the correct interpretation then you want the complement of dying in the first 1 or 2 years.
On prob 2, I know this is a combination question but it deals with a 0 which I don't know how to do.
The number of ways of choosing 3 cans from 29 is 29 choose 3. If you disregard the 8 cans of grape juice then the number of ways of choosing 3 cans from 21 is 21 choose 3.
On number 3, I have the event is 4 independent misses. So P(E) is .10 to the power of 4 which is .0001 is this the way to do this problem?
Yes.
Num 4. If a region has a 1/5 probability that a hurricane will hit then the odds that it will hit at least one in next five years is 1?
I think, like in problem 3 you should assume that the event of being hit by a hurricanes in any year is independent of whether you are hit in any other year. Find the probability that you don't get hit in any of the next 5 years and then take the complement.
No. 5 This one has so many factors I don't know how to set it up. Can you help me?
This is a conditional probability question. You want to know the probability that the second worker chosen has been doing illegal activities given that the first person chosen has not has been doing illegal activities. So after the first person is chosen there are 33 workers left. 25 of them have not been doing illegal activities and 8 of them have. Thus if you choose one of these workers at random the probability is 8/33 that this worker has been doing illegal activities.
Harley
