| Carolyn For 8 players:Round 1
 1 2 3 4
 5 6 7 8
 Round 21 2 5 6
 3 4 7 8
 Round 31 2 7 8
 3 4 5 6
 Round 4Any arrangement - in the first three rounds, every player has played with every other player at least once
 Note - it would be impossible for every player to play with every other player EXACTLY once
 
 For 12 players (a number or letter represents a player):Although I can't prove it, this seems to be impossible
 Paul |