Carolyn
For 8 players:
Round 1
1 2 3 4
5 6 7 8
Round 2
1 2 5 6
3 4 7 8
Round 3
1 2 7 8
3 4 5 6
Round 4
Any arrangement - in the first three rounds, every player has played with every other player at least once
Note - it would be impossible for every player to play with every other player EXACTLY once
For 12 players (a number or letter represents a player):
Although I can't prove it, this seems to be impossible
Paul
|