Question: hello!

Can somebody solve for n in the following equation please?

[(400/n)-5](n+ 4)=400

Thanks for your help and time geomar

Hi,

I would first multiply both sides by n to eliminate the fraction.

[(400/n)-5](n+ 4) = 400 n [(400/n)-5](n+ 4) = n 400 [400 - 5n](n + 4) = 400n

Now expand the left side

400n + 1600 - 5n^{2} - 20n = 400n

Can you finish it now?

Penny