



 
Hi Jason, Let's try a slightly different problem.
Let (x, y) be on the locus then its distance from (1, 0) is the square root of (x  1)^{2} + (y  0)^{2} and its distance from (3, 2) is the square root of (x  3)^{2} + (y + 2)^{2}. Thus
Square both sides to get
or
Expand what is inside the square brackets on each side and simplify. I got
Since the coefficient of x^{2} is equal to the coefficient of y^{2} this is the equation of a circle. If you wish you can put this equation into a more standard form. I got
Now try your problem, 



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