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           From: Kenneth 
          How can the following be solved without using algebra? 
          10 times some number is 3 times the same number plus 14. Answer: 2. 
                      I have a calculation, but I know it is not what the authors used to 
            determine the answer because the topic of algebra was not yet 
            mentioned in the section of the book. It is as follows: 10x = 3x + 14. 
           
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           Hi Kenneth. Paul sends us three methods not involving algebra:  
          Method 1 - trial and error 
            Make any guess: let's try 20 
            ten times 20 is 200 
            three times 20 plus 14 is 74 
            Not equal so try again - the guess is too big 
             
            Let's try 10 
            ten times 10 is 100 
            three times 10 plus 14 is 44 
            Not equal so try again - guess is still too big 
             
            Let's try 5 
            ten times 5 is 50 
            three times 5 plus 14 is 29 
            Not equal so try again - guess is still too big 
             
            Let's try 1 
            ten times 1 is 10 
            three times 1 plus 14 is 17 
            Not equal so try again - now guess is too small 
             
            Let's try 2 
            ten times 2 is 20 
            three times 2 plus 14 is 20 
            Therefore, the answer is 2. 
             
            Method 2 - using multiples 
            Multiples of ten always end with a zero 
            The multiples of 3 are: 3, 6, 9, 12, 15, ... 
            We need a multiple of 3 such that when 14 is added to it, the answer ends with zero (is a multiple of 10) 
            The multiples of 3 plus 14 are: 17, 20, 23, ... (the second one in this list has the desired property) 
            three times 2 plus 14 is 20 
            ten times 2 is 20 
            Therefore, the answer is 2. 
             
            Method 3 - reasoning with objects 
            Suppose some object, like a block, represents the answer. 
            Then, the problem translates to: 
            10 copies of the block is the same as 3 copies of the block plus 14 
            Thinking in terms of balancing weight: 
            10 blocks will balance 3 blocks plus 14 
            But 10 blocks is the same as 3 blocks plus 7 blocks, so: 
            3 blocks plus 7 blocks will balance 3 blocks plus 14 
            By "removing" the three blocks on each side, we are left with: 
            7 blocks will balance 14 
            Hence, each block must be 2 (since 2+2+2+2+2+2+2=14). 
            Therefore, the answer is 2. 
             
            Paul Betts  
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