Hi Sam,
I got the same second derivative as you. I also don't see a solution to
x^{4}4x^{3}+4x^{2}+4x+3 = 0 and I don't know a nice way to show that is has no solutions. I used Mathematica to sketch a graph of y = e^{x}/(x^{2}1) for x between 2 and 5 and I got
Graph of y = e^{x}/(x^{2}1)
The curve changes concavity at x = 1 and x = 1 but I don't believe there are any inflexion points.
Then I had Mathematica solve x^{4}4x^{3}+4x^{2}+4x+3 = 0 and it gave me four solutions, none of which are real so your conclusion is correct, there are no inflexion points.
Penny
