Hi Scott.
The notation 8  5r / 6 = 3 can be confusing. We do multiplication and division before addition and subtraction so I am reading this as
8  ^{5r}/_{6} = 3
Just remember that when you are trying to solve an equation, whatever you do to one side you must do to the other.
Here's a similar question:
11  2y / 3 = 5
You want to isolate the variable (y in this case) on one side of the equation. Paying attention to the order of operations, we do this in steps:
subtract 11 from both sides:
11  2y / 3  11 = 5  11
2y / 3 = 6
divide by 2 on both sides:
(2y / 3) / (2) = (6) / (2)
y / 3 = 3
now multiply by 3 on both sides to solve the problem:
3 ( y / 3) = 3 ( 3)
y = 9.
Last step is always to check your answer by putting the value in the original equation:
11  2y / 3 = 5
11  2(9) / 3 = 5
11  18 / 3 = 5
11  6 = 5
5 = 5.
Hope this example helps,
Stephen La Rocque
