Umar,
You can use differences to see how to generate the terms in the sequence.
sequence |
1 |
|
7 |
|
15 |
|
26 |
first differences |
|
5 |
|
8 |
|
11 |
|
second differences |
|
|
3 |
|
3 |
|
|
If the second differences are all 3's then I can see how to generate the next term. The next second difference is 3 so the next first difference is 11 + 3 = 14 and thus the next term in the sequence is 14 + 26 = 40.
sequence |
1 |
|
7 |
|
15 |
|
26 |
|
40 |
first differences |
|
5 |
|
8 |
|
11 |
|
14 |
|
second differences |
|
|
3 |
|
3 |
|
3 |
|
|
And now you can generate the next term and so on but you asked for an expression for the nth term. To do this I need some notation. I am going to call the nth term of the sequence xn and the nth first difference dn . Then the table of differences around the nth term looks like
sequence |
xn-2 |
|
xn-1 |
|
xn |
first differences |
|
dn-1 |
|
dn |
|
second differences |
|
|
3 |
|
|
Thus
dn = xn - xn-1
dn-1 = xn-1 - xn-2 , and
dn - dn-1 = 3
Substitute the values for dn and dn-1 from the first two equations into the third equation and solve for xn. This will give you an expression for xn in terms of xn-1 and xn-2.
Penny
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