Bob grade 12 Here's a problem I'm working on myself.....If you look at six consecutive spins of a roulette wheel, how many combinations of red and black are possible? I.E. BRRBRB, BBBBBR, BBRRRB......ETC..... Hi Bob, This is the same number as the number of Heads-Tails outcomes if you flip a coin 6 times: The roulette is a more complex appartus, but if you picture the head side of a coin being red and the tail side being black, you see that the possible outcomes are the same. There are two possibilities for the first spin (or flip): red or black Again there are two possible results for the second spin, ``` red black / \ / \ red black red black ``` giving 2*2 = 4 possible outcomes for the first two spins. For the third spin there are again two possible results ``` red black / \ / \ red black red black / \ / \ / \ / \ r bl r bl r bl r bl ``` giving 4*2 = 8 possible outcomes for the first three spins. And so on: Each spin can yield two possible results, so the number of possible outcomes of 6 spins is 2*2*2*2*2*2 = 64. Claude Go to Math Central