I am a student. Need to find a 4 digit number that can be divided by 2, 3, 4, 5, 6, 7, 8, 9, and will always have a remainder of 1 in the answer. Hi Dean,First look for a four digit number that gives a remainder of zero in each case and then add one to get remainders of one. What you are then looking for is the least common multiple (LCM) of 2, 3, 4, 5, 6, 7, 8 and 9. Begin by finding the prime factors of each nine numbers. 3 = 3^{1} 4 = 2^{2} 5 = 5^{1} 6 = 2^{1}3^{1} 7 = 7^{1} 8 = 2^{3} 9 = 3^{2} Looking at the highest power of each prime in the list above, the least common multiple is Penny
