Subject: Integration and Equations Question: Hi I've got a question concerning Integration and equations. I'm not sure what symbol to use for the squigly line for integration so I've just used the "&" key and I've put the definite limits directly after the "&" symbol separated by commas, the top one first and the bottom one second. Ok the question is: If a>0 &b,0 1/(1+x)dx = 1/2&a,0 1/(1+x)dx Express "b" in terms of "a" Here's the work I've done so far Log[1+x] = 1/2(Log[1+x]) Log[1+b]Log[1+0]=1/2Log[1+a]1/2Log[1+0] Log[1+b]=1/2Log[1+a] At this point I'm not sure if I can divide accross by Log or whether I have to bring the Logs over to one side and procede with Log subtraction. Either way I don't get the right answer which is: b=(1+a)^{2}1 Please help me with this one, Thanks Hi,At the point where you are stuck, Log[1+b]=1/2Log[1+a], use the identity cLog[t] = Log[t^{ c}] on the second factor. Cheers,Claude
