Hi! I have two questions involving dividing polynomials by polynomials.
Here's the first one:
Thanks a lot for your help!Hi Janna,
I would first calculate (a - 2)(2a + 1 ) = 2 a2 - a - 2. Since (a - 2) and (2a + 1) are factors of your quartic polynomial there are integers p, q and r so that
If you expand the right side by multiplication then the coefficient of a4 is 2p. But the coefficient of a4 on the left side is 12. Thus 2p = 12 and hence p = 6.
In a similar fashion, the constant term on the right side is -2r and the constant on the left side is 12. Thus r = -6.
Now find the coefficient of a on the right and left sides, set them equal and solve for q. Once you have p a2 + q + r you can factor it to answer the question asked.
You can approach problem 2 is a similar way. Since the division