Name: John

Who is asking: Student Level: Secondary

Question: I'm in a AP Calculus course and cannot solve the following series! And help would be greatly appreciated!

Sincerely, John

summation(n=1 to infinity)[n sin(1/(2n))]ⁿ

First take the absolute value of each term and then apply the root test on this series. The nth root of |n sin(1/(2n))|ⁿ is |n sin(1/(2n))| and you can evaluate

by making the substitution k = ¹/_2n.