Name: John

Who is asking: Student Level: Secondary

Question: I'm in a AP Calculus course and cannot solve the following series! And help would be greatly appreciated!

Sincerely, John

summation(n=1 to infinity)[n sin(1/(2n))]n

Hi John,

First take the absolute value of each term and then apply the root test on this series. The nth root of |n sin(1/(2n))|n is |n sin(1/(2n))| and you can evaluate

by making the substitution k = 1/2n.

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