Name: Justin Who is asking: Student Level: Secondary Solve the following equations for x x+7=10 x= x-7=10 x= 3x=7 x= x/3=10 x= x/2+x/2=25 x= 5x-2=3x+8 x= 3(x+2)=4(x-1) x= x+3/2=2x-7/7+3 x= Hi Justin, I like the "balance anology" for equations of this sort. In your first equation you have a balance with a "weight" of x+7 on one side and a "weight" of 10 on the other. The object is to manipulate the weights, without upsetting the balance, so that you end with only the variable x on one side and a number on the other, that is x=... In the first problem x + 7 = 10 if you subtract 7 from both sides, the balance is maintained and you get x + 7 - 7 = 10 - 7 or x = 3 You should now check to see that "x = 3" is correct. In the original equation, x + 7 = 10, substitute x = 3 to see if you really do have a balance. When x = 3 the left side of the equation is x + 7 = 3 + 7 = 10 which is the same as the right side and hence x = 3 is correct. Now try the others. If you have trouble it might help to look at my solution to Kelley's problem. Cheers, Penny Go to Math Central