Name: Kaleena
Who is asking: Other
Question: The first feature I see in this expression is that every term has an x in it. That allows me to take out an x as a common factor. Hence = x(5x^{6}  10x^{4} + 4x^{2}  8) What I see next is more subtile. I am going to group the terms because I see that 10 is twice 5 and 8 is twice 4. = x[(5x^{6}  10x^{4}) + (4x^{2}  8)] = x[5x^{4}(x^{2}  2) + 4(x^{2}  2)] Now the two terms inside the brackets have a common factor of x^{2}  2. (This is the subtile observation I made when I observed that "10 is twice 5 and 8 is twice 4".) Thus = x[(5x^{4} + 4)(x^{2}  2)] A significant part of factoring is "pattern recognition". You need to be able to look at an expression and recognize something familiar. It's like hearing the first bar of a song and recognizing the group even if you haven't heard that exact song before. Harley
