Who is asking: Other
Question: I make mirror frames using a technique called kerf bending. If your unfamiliar with woodworking, a saw kerf is simply the gap that remains after the table saw blade passes through the board. If the blade is raised to a height slightly lower that the thickness of the wood, then the board can be “bent” by applying a bending moment until the kerf, or series of kerfs, pinch closed. Using a frame material width of 17/8” and by cutting kerfs of 15/8”(leaving a 1/8” strip of wood around the edge) I‘ve determined that 20 such kerfs will allow me to bend the material 90 degrees. By cutting a series of 80 kerfs, spaced in a particular way I can make an elongated hexagonal frame out of one board. Simply cut the kerfs, bend the board all the way around until the ends touch, clamp it in place, I then fill the pinchedclosed kerfs with tinted epoxy, sand off the strip of wood around the edge (effectively making 80 distict pieces of wood with epoxy wedges in between), and it makes a coo! ! l looking mirror frame. (I hope your still interested at this point.) Anyway, I'm bored with the hex shape and want to make a elliptical frame using the same technique and wood width (360/80=4.5 degrees of bend per kerf). I found an ellipse in my old calculus book that is esthetically pleasing: x^{2}/25 + y^{2}/9=1. This ellipse is the wrong “size” of course, but it is the "right" shape. What is the equation (with the length of the arc as a variable) for one quadrant of the ellipse, that will generate the spacings for the kerfs (20 per quadrant) such that the final shape will be close to the desired ellipse. Thanks you very much for your time. Hi,You stumbled upon a tough question there; you may never have seen it in calculus. The ellipse you like has the parametric equation
