Name: John Read I'm not sure I'm at the right place for help with this problem. It's related to a project I'm involved with, but not a school/exam etc. Still, it's driven me nuts for three days now, so I'll ask in hope. I have three dice (A, B, C.) Three sides of each dice are blank. Three sides of each dice have a number. When the dice are thrown, it must be possible to result in the numbers 1 to 49 in any combinations without doubling up on any figure. i.e. Different combinations resulting in the same end number. I managed to get from 1 to 47 before getting stuck. e.g. A: 1. 2. 3. B: 4. 8. 12. C; 16. 32. /. This needs to be scrapped and started again.... and boy have I tried. If anyone can help, then thanks in advance. If I'm wasting your time, accept my apologies. Best Wishes John Read Hi John, The possible outcomes are for dice A: blank, first number, second number, third number; for dice B: blank, fourth number, fifth number, sixth number; for dice C: blank, seventh number, eighth number, ninth number. In all, you get 4*4*4 = 64 possible outcomes: this can be all blanks plus all the numbers from one to 63 (by putting 48 on the last dice). However, it is impossible to limit the outcomes to the numbers up to 49 without having some outcomes repeated. Cheers, Claude Go to Math Central