I need some help with the following problems:
- Show that the product of the solutions of ax2 + bx + c = 0 is c/a.
- For each equation under the given condition,
(a) find k and
(b) find the other solution.
kx2 - 2x + k = 0; one solution is -3
For question 1 first divide both sides by a to get
x2 + b/ax + c/a = 0
Suppose that the solutions are p and q, then
x2 + b/ax + c/a = (x - p)(x - q) = 0
Multiply (x - p)(x - q) to find p times q.
For question 2, use what you know from question 1. The product of the sulutions is c/a and in this equation a = c = k. Thus the product of the solutions is k/k = 1.
Go to Math Central