Can't get the solution to a question on combinations.
From a standard deck of cards how many 5 card hands are possible consisting of
b. two cards of one kind and three of another(like a full house).
Is part a 13!/9!4!?
part b not sure.
You have part a almost correct. 13!/9!4! is the number of ways of choosing 4 cards from the 13 hearts in the deck. But you want a 5 card hand with exactly 4 hearts. Thus you can select the final card from the 39 that are not hearts. Hence the number of 5 card hands with exactly 4 hearts is
For part b you can select the first kind in 13 possible ways. From the 4 cards of that kind select 3, which you can do in 4!/3!1! ways. Thus far you have
Now choose one of the 12 kinds rremaining and select 2 of the 4 cards of that kind. That you can do in
Hence there are