Hello, I've come up with an answer for the following problem but it's not the same as the book's answer. However, the book has a lot of mistakes in it and I don't know if I'm doing it properly or not. Your help would be soooo appreciated. It's driving me crazy.The problem is:

  2               + 3          + 4
---------  +  ---------  +  ----------
(x-1)^3        (x-1)^2       (x-1)

[(x-1)^3 is (x-1) to power of 3 etc.]

Thank you


Hi Francine,

The first chore is to get all three fractions to have a common denominator. The best choice here for that denominator is (x-1)3. To accomplish this multiply the numerator and denominator of the second fraction by (x-1) and multiply the numerator and denominator of the third fraction by (x-1)2. The result is

The expression in the numerator doesn't factor so there is no further simplification.

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