Hello, I've come up with an answer for the following problem but it's not the same as the book's answer. However, the book has a lot of mistakes in it and I don't know if I'm doing it properly or not. Your help would be soooo appreciated. It's driving me crazy.The problem is: 2 + 3 + 4  +  +  (x1)^3 (x1)^2 (x1) [(x1)^3 is (x1) to power of 3 etc.] Thank you Francine Hi Francine,
The first chore is to get all three fractions to have a common denominator. The best choice here for that denominator is (x1)^{3}. To accomplish this multiply the numerator and denominator of the second fraction by (x1) and multiply the numerator and denominator of the third fraction by (x1)^{2}. The result is Penny
