Hi my math teacher asked us to solve an augmented matrix. I am in twelfth grade and need help. The book we are working on is college algebra. Here it is
a+2b+c=0 Thank you for your help Hi, The augmented matrix is formed by taking th matrix of coefficients and "augmenting it" by appending a column containing the numbers on the right side of the equations. For your problem the augmented matrix is b = ?? c = ??? Start with the first column. I would like to transform the 2 in the second row to 0. To do this I will multiply the forst row by 2 and add it to the second row. (If you think in terms of the equations you started with, this is multiplying the first equation by 2 and adding it to the second equation.) Performing this operation gives The first column is now in the form I want so I can now turn my attention to the second column. I want the 3 in the third row to be 0 and I can arrange this by multiplying the second row by 3 and adding it to the third row. This gives Finally the third column. I want the entry in the third row of the third row to be 0 rather than 4. To accomplish this I multiply the third row by  ^{1}/_{4}. (This is the same operation as multiplying both sides of an equation by  ^{1}/_{4}.) The resulting matrix is I leave it to you now to complete the problem by transforming the third column into the desired form. A nice feature of this problem is that you can verify your answer. Once you have values for a, b and c you can substitute them into the original equations to see if they are valid. Cheers,Penny
