Name: sarathy Solve : 1! + 2! + 3! + ... + x! = y^{ 2} How do i find the solutions ? Hi,There cannot be that many; can you find the small ones?
Now suppose that x is big, and look at the remainder of the division of
1! + 2! + 3! + 4! + 5! + ... + x! by 5.
What does this tell you? Claude
