There is a formula connecting any (k+1) successive coefficients in the nth row of Pascal's Triangle with a coefficient in the (n+k)th row. find this formula.

My name is Timothy . This is a secondary level question (11th grade) A Student is asking this.

You should repeatedly apply Pascal's Identity on two coefficients in the nth row adding up to one in the next row to see what happens to k+1 successive coefficients. Now apply the same technique to the k coefficients you have just produced the the (n+1)st row. Continue to repeat with successive rows. Once you've got to the (n+k)th row, work backwards to see how many each of the coefficients in the nth row you need to get the one you ended up with on the (n+k)th row.