(x+1)(x+2)=? Hi there,
For your first question you are multiplying a binomial by a binomial. You can do this by applying the distributive property you are already familiar with and reduce the problem to one of multiplying a binomial by 2 monomials. I will illustrate this: = (x)(x + 2) + (1)(x + 2) = x2 + 2x + x + 2 = x2 + 3x + 2 For your second question you need to remember that if 2 numbers multiplied together result in zero, then either one of the terms is zero, or both of the terms is zero. You need to find which values for x will result in the whole expression being zero. So either (2x - 1) is equal to zero, or (x - 4) is equal to zero (or both of them are). Can you see how to solve for which values of x make (2x-1)(x-4)=0 now? Hope this helps, Leeanne
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