Quandaries and Queries


Who is asking: Parent
Level: All

A rectangular corral is forty feet longer than it is wide. If the perimeter is 220 feet, determine the length and width of the corral.




I would draw a diagram. This is the diagram I drew.

I need to put some labels on the diagram so that I can tell you how it helped me solve the problem.

Since the corral is 40 feet longer than it is wide I put a point E on the side AB so that the length of AE is the same as the length AD. Thus the length of BE is 40 feet. In a similar fashion I put the point F on CD so that the length of CF is 40 feet. Thus the lengths of AE, BC, FD and AD are all the same. If I just knew that length I would know the perimeter.

To set up an equation let this unknown length be x feet. Then I know that

perimeter = 220 feet
= |AE| + 40 + |BC| + 40 + |FD| + |DA|
= x + 40 + x + 40 + x + x = 4x + 80


4x + 80 = 220

Now solve for x, which is the width of the corral.



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