Quandaries and Queries
 

 

Subject: maxima problem

Name: evelina

Who is asking: Student
Level: Secondary

Question: Hi, I'm having troubles with taking the derrivative in this maxima problem.

Here's the actual question and my work so far...

A window is the shape of a rectangle with an equilateral triangle on top. The perimeter of the window is 300 cm. Find the width that will let the maximum light to enter.


 
   /\	   let y be the length of the
y /  \ y   sides of the triangle and
 /____\	   width of the rectangle in cm
 |  y  |   let x be the length of the
 |     |    rectangle in cm
x|     | x
 |_____|
    y
    

Maximize:

Area= (area of rectangle) + (area of triangle)


       3^(1/2)
= xy + ------ y^2   *1*
          4
Given:

Perimeter= 300cm

2x + 3y = 300

x = 50y    *2*

Sub *2* into *1*


           3^(1/2)
A= 50y^2 + ------- y^2
              4
For maximum,

 dA
---- = 0
 dy
 
 dA
---- = 100y + ????
 dy
 

This is where my problem is. I cannot figure out how to take the derrivative of the square root of 3 etc. I've come up with many different answers but I know none of them work, when I set the derivative equal to zero I always get y to equal zero. Did I set up the problem incorrectly or is my problem just not knowing how to take the derrivative?

Thanks so much for your time,
Evelina

 

 

Hi Evelina,

The square root of 3 divided by 4 is a constant just like 50 is a constant so if

then

The rreason that this answer "doesn't work" is that there is an error in your equation *2*. Since the perimeter is 300 cm you have correctly that

2x + 3y = 300 however, solving for y you should get 3y = 300 - 2x and hence y = 100 - 2/3 x       *2*

Substitite this equation *2* into *1* and differentiate.

Cheers,
Penny
 
 

Go to Math Central