 Quandaries and Queries I am a 3 digit number. My last digit is 3 times my first digit. My firat digit is twice my middle digit. What numbers am I? There are at least 2 correct answers? Thank you One possible solution - My last digit is 3 times my first digit: This statement says alot. First, the last digit must be a multiple of 3, so it is either 3, 6 or 9. Second, given the last digit, we know the first digit must be 1, 2 or 3, respectiviely. Thus, the number is: 1_3, 2_6, or 3_9. My first digit is twice my middle digit: This statement says the first digit must be a multiple of 2, that is, the first digit is even. This means of the three possibilities generated above, only one can be used, namely, 2_6. Thus, the answer is 216. Unless you allow 000 as a 3 digit number, there is only one possible answer! Another solution - Above I assumed the the units digit was the 3rd digit. In this solution, I will assume that units is 1st, tens is 2nd, and hundreds is 3rd. My last digit is 3 times my first digit: The possibilities now are: 3_1, 6_2, or 9_3. My first digit is twice my middle digit: First digit ie even so the only possibility from above is 6_2. Thus, the answer is 612. Again, a unique answer, although different from solution 1 since assumed aĘreversed order of digits. Now I have a request for you: Please let me know if you find another solution, or discover if there is a problem with the wording of this question. Paul Go to Math Central