Quandaries and Queries


Who is asking: Student
Level: Secondary


// = the main fraction line

1.) a+1/a-1 + a-1/a+1 // a+1/a-1 - a-1/a+1

2.) 2/a(squared)-3a+2 + 2/a(squared)-a-2 // 2/a(squared)-1 + 2/ a(squared)+4a+3




I'll help you get started by looking at the first problem. The numerator is

 a+1/a-1 +  a-1/a+1 A common denominator is (a-1)(a+1) so this can be written  (a+1)(a+1)/(a-1)(a+1) +  (a-1)(a-1)/(a+1)(a-1)

[(a+1)2 + (a-1)2] /(a-1)(a+1)

Likewise the denominator can be written

 [(a+1)2 - (a-1)2] /(a-1)(a+1)

Thus the fraction in problem 1 reduces to

 [(a+1)2 + (a-1)2] /[(a+1)2 - (a-1)2]


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