Hi my name is Patty and I am taking a pre-calculus course and need help with the following. Question If sin0 = 7/8 and 0 is in quadrant 2, find the other five trigonometric functions of 0. (report your answers in radical form) I'm also not sure how to show (0) with a line through it so I have just used the zero key. What is radical form? would this be how I answer this? sin2 0 + cos2 0 = 1 (7/8)2 + cos2 0 = 1 cos2 0 = 1 - 49/64 = 15/64 cos 0 = sq root of 15/64 = 1/8 sq root 15 and tan 0 = sin 0/cos 0 = 7/8 / 1/8 sq root 15 = 7/sq root 15 (not sure about the math here?) = 1.8 and cot 0 = 1/tan0 = 1/ 7/sq root 15 = sq root 15/ 7 = .55 and sec 0 = 1/cos 0 = 1/ 1/8 sq root 15 = 1/8 sq root 15 = .48 and csc 0 = 1/sin 0 = 1/ 7/8 = 8/7 = 1 1/7 does any of this make sense and if so is it right? Thank you Patty Hi Patty, You missed one important point in the question, the fact that the angle is in the second quadrant. (I am going to use t for theta, rather than O. I worry about confusing O with 0.) I agree with your solution to the fact that cos2 t = 1 - 49/64 = 15/64 but, since t is in the second quadrant, cos t is negative. Thus cos t = - 1/8 sq root 15 This is cos t in radical form, It involves rational numbers and roots, but no decimals. Since the tangent is the sine over the cosine tan t = - 7/sq root 15 (don't use the decimal approximation, leave the answer in this form.) For the remainder of the problem make sure that you check the signs and remove the decimal approximations. Penny Go to Math Central