Shelley these two questions are to be factored completely but i have no idea how to factor them - (x-4y)
^{ 2}- 3(x-4y) - 4 - x
^{ 6}+ y^{ 6}
Hi Shelley, A great deal of algebra is pattern recognition. The ability to look at an expression and see a pattern. Not unlike hearing the first two bars of a song and recognizing what it is. In your first problem the key is to look at ^{ 2} - 3(x-4y) - 4
^{ 2} - 3z - 4
Let z = x - 4y, then ^{ 2} - 3(x-4y) - 4= z ^{ 2} - 3z - 4= (z - 4)(z + 1)
For the second problem you know how to factor a sum of cubes. But (x ^{ 6} + y^{ 6} = (x^{ 2})^{ 3} + (y^{ 2})^{ 3}
^{ 2} and t = y^{ 2}, substitute into the expression above, and factor as a sum of cubes.
Cheers,Penny To return to the previous page use your browser's back button. |