Hi I'm the aunt of a middle school child. He need help with two problems and I don't understand how to show he how to do them. Can you help me.

  1. How do you find the perimeter for X=4, X=0.7, and X=5/6?

  2. And an acute triangle that bottom is (3X+1) cm, left side is (X+4) cm and the right is (2X+5)cm.

Can you show me not only the answer but also the steps that you used.


The perimeter of a geometric shape is the length of its boundary. For example the perimeter of a field is the length of fence it takes to surround the field. For your triangle in the first problem the sides are of lengths 4, 0.7 and 5/6. Hence the perimeter is

4 + 0.7 + 5/6 = 4 + 0.7 + 0.8333 = 5.5333

Likewise for the second problem the perimeter is

(3X+1) + (X+4) + (2X+5)
= 3X + 1 + X + 4 + 2X + 5
= 6x + 10

I hope this helps,

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