i have this difficult question my student asked me today. Our whole class was discussing it. I am wondering what is the way to solve this problem? Given AB||CD; m<D = 116 AK bisects <DAB
a. Find the measures of <DAB, <KAB, <DKA
D C _____________K______ (there is a line supposed to be connecting / / A and K ) / / /___________________/ A B
Since the lines AB and CD are parallel, angles CDA and DAE are equal, each with an angle measure of 116o.
Since EAB is a line, angle DAB has measure 180o - 116o = 64o. Hence angle KAB has measure 32o. Since the measures of the three interior angles of a triangle sum to 180o, you can find the measure of angle DKA.
There is nothing in the problem that specifies where B is except that it is on the line through A and parallel to DC and hence there is no requirement that <D adn <C are supplementary.Penny
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