Question: dx/(2+cos x) i used the substitution t=tan(x/2) and i ended up with integral from +infinity to 0 of
2dt/(t which looks like an inverse tan function , and i ended up with sqr(27)/2 pi , which is not the same as my calculator's answer , so i suspct i am doing some thing wrong. can some one tell me where i am going wrong please. Hi, I would do this integral exactly as you did with a t=tan(x/2) substitution and then an inverse tangent. This gives me ^{2}/_{sqrt(3)} arctan( ^{tan[x/2]}/_{sqrt(3)})
Evaluating this from pi to 0 I get You can check the integration using Mathematica at The Integrator. You need to take some care with Mathematica's notation. Input the expression To return to the previous page use your browser's back button. |