Quandaries and Queries


Who is asking: Student
Level: Middle

I am having some serious problems with the last question on my Independent Study Unit. The question is A spherical snowball has diameter 10cm and density 0.75g/cm3. It is placed in a cylindrical can with diameer 12cm. After the snow melts it turns to water with density 1.0g/cm3. What will be the depth of the water in the can (to 1 decimal place)?

Well that's it I really don't understand it so it would be a great help if you could figure it out.




As the snow melts and changes to water the mass remains constant but the density changes, so the volume changes. Use the expression for the volume of a sphere

V = 4/3 pi r3

to find the volume of the snowball in cubic centimeters. Every cubic centimeter weighs 0.75 grams and thus you can find the mass of the snowball.

When the snowball melts its mass (now water) remains the same and since the density of water is 1.0g/cm3you can find its volume. The water is in a cylinder of diameter 12 centimeters, and thus radius of 6 centimeters. The volume of a cylinder is

V = pi r2 h

You know V and r and thus you can find h.



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