In a triangle i have the length of a line and it's opposite angle.how can i calculate perimeter?(the angles are not right)
Hi,
There is not enough information here to calculate the perimeter. Let me illustrate with an example.
I am going to use an equilateral triangle PQR with all sides of length 1 so the angle RPQ is 60o.
Let S be a point on the line segment PR which is very close to P. Extend the line segment PQ. Let T be the point on PQ extended such that the length of ST is 1, that is |ST| = 1.
PQR and PTS are two triangles. Each has a side of length 1, QR and TS, and the angle opposite this side is 60o in each triangle.
The perimeter of PQR is
1+1+1=3.
The perimeter of PTS is
|PT| + |TS| + |SP|
= |PQ| + |QT| + |TS| + |SP|
= 1 + |QT| + 1 + |SP|
= 2 + |QT| + |SP|
But |QT| and |SP| are both very small, in fact you can make them as small as you want by taking S very close to P. Thus you can ensure that |QT|+|SP| is less than 1 and hence the perimeter of PTS is less than 3.
Penny