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In a triangle i have the length of a line and it's opposite angle.how can i calculate perimeter?(the angles are not right) 

Hi, There is not enough information here to calculate the perimeter. Let me illustrate with an example. I am going to use an equilateral triangle PQR with all sides of length 1 so the angle RPQ is 60^{o}. Let S be a point on the line segment PR which is very close to P. Extend the line segment PQ. Let T be the point on PQ extended such that the length of ST is 1, that is ST = 1. PQR and PTS are two triangles. Each has a side of length 1, QR and TS, and the angle opposite this side is 60^{o} in each triangle. The perimeter of PQR is
The perimeter of PTS is
But QT and SP are both very small, in fact you can make them as small as you want by taking S very close to P. Thus you can ensure that QT+SP is less than 1 and hence the perimeter of PTS is less than 3. Penny 

