Quandaries and Queries
 

 

Question:
Having trouble with this one.

There are 5 white and 5 yellow balls in a golf bag. Two are selected randomly, and simultaneously. What is the probability that the first one or the second one will be white?

 

 

Hi,

I would draw a tree diagram. On my diagram W is selecting a white ball and Y is selecting a yellow ball.

There are 4 ways to progress through the tree and 3 of them have at least one white ball being selected. The only path through the tree with no white ball selected is to obtain a yellow ball on the first selection and a yellow ball on the second selection. From the tree diagram the first has probability 5/10 and the second has probability 4/9. Thus the probability that you select no white balls is

5/10 4/9 = 2/9

Hence the probability that either the first ball is white or the second ball is white is

1 - 2/9 = 7/9

Penny

 
 

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