 Quandaries and Queries Hi my name is Angela and I am in High School. I not going to give you the problem that I have, but a problem like it. 4(r-2) = r(2+8) I get mix up trying to solve a problem like this could you help me. So that I will be able to handle the ones on my homework.   Angela Hi Angela, Look at the right side of this equation, r(2+8). There are two ways I can evaluate this expression. Add 2+8 and then multiply by r. r(2+8) = r(10) = 10r Multiply by r first, and then add r(2+8) = r2 + r8 = 2r + 8r = 10r On the left side, r - 2 can't be simplified further so option 1 above isn't available. I can, however expand the left side as I did in the second option 4(r - 2) = 4r - 4 2 = 4r - 8 Thus your equation is 4(r - 2) = r(2 + 8) 4r - 8 = 10r The goal is to "solve for r", that is to manipulate this equation to put it in the form r = "number" I don't want an r on both sides and I can accomplish that by adding -4r to both sides 4r - 8 = 10r -4r + 4r - 8 = 10 - 4r -8 = 6r Now divide both sides by 6  -8/6 = 6r/6  -4/3 = r Thus r = -4/3 Penny Go to Math Central