Quandaries
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My problem is as follows: An isosceles trapezoid with bases of lengths 12 and 16 is inscribed in a circle with a radius of 10. The center of the circle lies in the interior of the trapezoid. Find the area of the trapezoid. Thanks for your help! Bruce |
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Hi Bruce, The area of a traposoid is the average of the lengths of the parallel sides times the distance between the parallel lines. I drew a rough sketch of your situation.
C is the center of the circle and triangle ABC is a right triangle so you can use Pythagoras' theorem to find |AC|. Can you complete the problem now? Penny |
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