Quandaries and Queries


I have a room that is rectangular the area is 159.5 feet, the perimeter is 51 feet what would the dimensions of the room.


Hi Estella,

Draw a diagram and label the lenght L and the width W.

The area of a rectangle is the length times the width so

L W = 159.5

The perimeter is the distance around the room so

L + W + L + W = 51


L + W = 25.5


L = 25.5 - W

Substitute this value for L into the first equation to get

(25.5 - W) W = 195.5

Simplify and solve for W.



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