Quandaries
and Queries
I have a room that is rectangular the area is 159.5 feet, the perimeter is 51 feet what would the dimensions of the room.
ESTELLA
Hi Estella,
Draw a diagram and label the lenght L and the width W.
The area of a rectangle is the length times the width so
L
W = 159.5
The perimeter is the distance around the room so
L + W + L + W = 51
thus
L + W = 25.5
Hence
L = 25.5 - W
Substitute this value for L into the first equation to get
(25.5 - W)
Simplify and solve for W.
Penny