Quandaries
and Queries 

Name: jason Who is asking: Other Question: 

Hi Jason, The difference method will work well here: form successive rows where the first row is your original sequence, and the kth term in the next row is always the difference between the (k+1)th term and the kth term in the previous row: 1st row: 1, 4, 10, 20, 35, 56, 84, ... If you can guess the 5th term in the 4th row, it will help you find the 6th term in the 3rd row, which will help you find the 7th term in the 2nd row, which will help you find the 8th term in the first row. You can then start over a few times, finding the next term in each sequence; after that, you will need to try to find a general expressions for the nth term in each row. Claude 

