Quandaries and Queries
 

 


|x2 - 12x| = 8

Thanks,
Sherre

 

 

Hi Sherre,

This is really two problems.

  1. If x2 - 12x ≥ 0 then |x2 - 12x| = x2 - 12x and hence
    |x2 - 12x| = 8 is x2 - 12x = 8 or x2 - 12x - 8 = 0. This equation you can solve by factoring or by using the general quadratic.

  2. If x2 - 12x < 0 then |x2 - 12x| = -(x2 - 12x) and
    |x2 - 12x| = 8 is -(x2 - 12x) = 8 or x2 - 12x + 8 = 0. This equation you can also solve by factoring or by using the general quadratic.

Penny

 
 

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