Quandaries
and Queries 

Name: Tim Kirkpatrick Level: 10th Grade Algebra Who: Parent Problem: The ratio of W to H was 7 to 9. The ratio of H to I was 9 to 5. If the sum of the W and H exceeded twice the number of I by 12, how many were W, how were H and how many were I? I have tried substitution, using the equalities below, replacing variables W & I with the corresponding values containing variable H. The problem with this is I end up with a negative sign for the H term after moving them all to the left, because of multiplying by 2. I don't know if I'm approaching this right or have the correct equalities set up. I have: 7W = 9H. (So W = 9H/7)? 9H = 5I. (So I = 9H/5)? And 5I = 7W? Used formula of H + W = 2(I) + 12 Thanks, Tim 

Tim, you need to be a bit more careful at the start:
Penny 

