Quandaries
and Queries 

name :Aamod (student) Difficulty: 7 Find the sum of the given series till n terms: (1^{4}\1*3) + (2^{4}\3*5) + (3^{4}\5*7)............... till n terms 

The sum (1^{4})/(1*3) + ... + (n^{4})/[(2n1)*(2n+1) equals the fraction whose top is n*(n+1)*(n^{2} + n + 1) and whose bottom is 6*(2n + 1) Is this the question you were asking? Chris 

