Quandaries
and Queries
name :Aamod (student)
Difficulty: 7
Find the sum of the given series till n terms:
(14\1*3) + (24\3*5) + (34\5*7)............... till n terms
The sum (14)/(1*3) + ... + (n4)/[(2n-1)*(2n+1) equals the fraction whose top is
n*(n+1)*(n2 + n + 1)
and whose bottom is
6*(2n + 1)
Is this the question you were asking?
Chris