Quandaries and Queries


What is the limit as x approaches 3 of
I'm having a lot of difficulty figuring this one out algebraically as you don't have to ratonalize the denominator.
Please help.Thank you very much.


Hi Abraham,

I would rrationalize the numerator by multiplying both the numerator and denominator by sqrt(x+1)-2.

This gives a numerator of

= [sqrt(x+1)]2 -22
= x + 1 - 4 = x - 3

and a denominator of

(x - 3)[sqrt(x+1)+1]

Since x is not 3 you can cancel the (x-3)Factors and get




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