Quandaries and Queries


Can you please explain to me how to factor completely the following problem:
Thank you so much.


Hi Abraham,

Since x2 +2x+1 = (x+1)2,

(x2+2x+1)-7/4) = (x+1)-7/2)1/ (x+1)7/2)

Now express the two terms you have with the common denominator of


I got the numerator to be

(x+1)( 1/2) (x+1)7/2) -1 = (x+1)4 -1

Finally factor the numerator as a difference of squares, and then one of the factors can be factored again as a difference of squares to give a numerator of

x (x+2)[(x+1)2 +1]




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