Question:
the 4th and 5th term of an arithmetic progration 47 and 52 respactively find
a)d
b)a_{1}
c)a_{50}

Hi,

This is an arithmetic sequence and d is the difference between successive terms. The 4th term is 47 and the 5th term is 52 so

d = 52 - 47 = 5

a_{1} is first term and hence you add d, four times to a_{1} to get to the 4th term 47. Thus you need to subtract d, four times from 47 to get back to a_{1}.

a_{50} is the 50th term so you ned to add d to a_{1} fifty times to get to a_{50}.