 Quandaries and Queries I'm having trouble figuring out how to figure a percentage??? it's easy to find what 40% of any given number is, but how would i accurately figure out what is the final number is when i know the number after the 40% has been removed? when i add 40% to this number it obviously is lower than it should be. the best i could figure is; x=?-40% ---------------> x-?=-40% i'm all confused???? any help would be greatly appreciated. Thanks much Hi Cathy, Think of what you do in the "forward" direction. If you have \$250 and you want to remove 40% of it you have \$250 - 40% of \$250 = \$250 - 0.4 \$250 =\$250 (0.6) = \$150 Now suppose that you buy something at a shop for \$150 and you know that the original price of this item was reduced by 40% to arrive at the \$150. If the original price was \$x then, looking at the equation above, the shopkeeper calculated \$x 0.6 = \$150 To find x, divide both sides by 0.6 to get (\$x 0.6)/0.6 = \$150/0.6 or \$x = \$250 A similar argument works if you want to add 40%. Suppose you bought an item for \$420 and you know that the shopkeeper's markup is 40%. Then the shopkeeper took her price, \$x, and multiplied by 1.4 to get the \$300 price. That is \$x 1.4 = \$420 Thus \$x = \$420/1.4 = \$300 So the shopkeeper paid \$300 for the item. Penny Go to Math Central