Question:Ω The gradiant of a hill is 9%. What angle is created by the run/rise of the hill and 0 degrees?

Hi Jim,

If the gradient is 9% = ^{9}/_{100} then the rise over the run is 9 over 100.

If t is the angle created by the hill and 0 degrees as in the diagram then

tan(t) = ^{9}/_{100} = 0.09

Hence

t = tan^{-1}(0.09)

Penny

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