Quandaries
and Queries 

Hi There I'm a parent How do you solve the problem of finding the cubed root of (17 to the power of 3). Also can you show a step by step of finding the cubed root of 27. Visuals help a lot Thanks a ton! 

Hi, The cube of a number is straightforward. The cube of 2 is 2 2 2 = 8 and the cube of 5 is 5 5 5 = 125. Finding the cube root is performing this process backwards.
This is the same problem as
Sometimes the solution is to just look at the question and say "Two times two times two is eight so the cube root of eight is two." This is the way I would solve your second problem. Do ou know a number n so that n times n times n is 27? The first problem is to find the cube root of 17^{3}. Since
the cube root os 17^{3} is 17. Penny 

