 Quandaries and Queries who is asking:student Level of question: middle   I Was working and i ran into this problem can you help me solve it using the substitution method?   -3x-2y=-10 x+5y=-27 and I have another question   4x=2y+23 x-6y=3 thanks Hi, Look at the first two equations -3x -2y = -10 x + 5y = -27 In the second equation add -5y to each side to get x + 5y -5y = -27 -5y and hence x = -27 -5y Thus I "solved for x in terms of y", in other words I have x = (some expression involving y but no x). Now take this expression for x and substitute it into the first equation -3x -2y = -10, therefore -3 ( -27 -5y) -2y = -10 Now simplify 81 + 15y - 2y = -10 81 + 13y = -10 13y = -10 -81 = -91 y = -91/13 = -7 Finally, since y = -7 you can substitute that value into x = -27 -5y to get x = -27 -5(-7) = -27 + 35 = 8 Hence x = 8 and y = -7. I could have started by "solving the first equation for x in terms of y" or either equation "for y in terms of x" but I made the choice I did since I could proceed without using fractions. Now you try the second problem and write back it you have difficulty. Penny Go to Math Central